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Grind the perimeter of a rectangle length 6yd. 2ft width 4 yd 18 in
Let's assign 6yd2ft as[tex]x[/tex] and 4yd 18in as [tex]y[/tex]. Because the shape is a rectangle, to find the perimeter, you would multiply the height and length by 2, [tex]2x+2y[/tex], so now if you substitute back in, you get 13yd 1ft + 9yd, which is 22yd 1ft.
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