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Sagot :
Answer:
Formula in factored form: 0= (5t+2)(t-5)
When the rocket will fall to the ground: 5 seconds
Step-by-step explanation:
We need to find when the rocket hits the ground given the quadratic formula.
What would be the height of the rocket when it hits the ground? The height would be 0 meters, where it touches the ground. Now set the formula equal to 0. We are solving for t, which is the time it will take in this context to hit the ground.
0= -5t^2+23t+10
What numbers multiply out to -50 and add to the middle term 23?
Those are factor pairs are 25, -2: 25-2= 23, 25*-2=-50
Now we can factor by grouping
0= -5t^2+25t-2t+10
0= (5t+2)(t-5) <--- take out GCF and simplify down
5t+2=0 , t-5=0 <---- Zero product property
Simplify and get t= -2/5, t=5
t= -2/5 is an extraneous solution. You cant have a negative time. If you were to plot this on a graphing calculator you would notice the graph hits the x-axis 2 times (2 roots/zeros). t=5 is the only reasonable root
Thus it will take 5 seconds for the rocket to fall toward the ground.
Answer:
[tex]\displaystyle five\:seconds[/tex]
Step-by-step explanation:
Factour this trinomial. Now, as you can see, there is a negative inserted in front of the trinomial. If you are afraid of negatives, easily factour it out and begin the factorisation process:
[tex]\displaystyle -5t^2 + 23t + 10 \hookrightarrow 5t^2 - 23t - 10 \\ \\ [5t^2 - 25t] + [2t - 10] \\ 5t[t - 5]\:\:2[t - 5] \\ \\ [t - 5][5t + 2][/tex]
Set the factors equal to zero to determine the time:
[tex]\displaystyle 0 = [t - 5][5t + 2] \\ \\ -\frac{2}{5}, 5 = t[/tex]
*Time is NEVER negative, therefore it will take five seconds for the rocket to hit the ground.
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