Anubhav99idn
Answered

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PLEASE SOLVE IT WITH FULL EXPLANATION!!
DONT STEAL POINTS :)​

PLEASE SOLVE IT WITH FULL EXPLANATIONDONT STEAL POINTS class=

Sagot :

Amphitrite1040idn

Hey there!


2^30+2^29+2^28 / 2^31+2^30+2^29


= 1,073,741,824 + 536,870,912 + 268,435,456 / 2,147,483,648 + 1,073,741,824 + 536,870,912


= 1,610,612,736 + 268,435,456 / 3,221,225,472 + 536,870,912


= 1,879,048,192 / 3,758,096,384


= 1 / 2


≈ 0.50

Therefore, your answer is: 1/2


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

We are given with a fraction which has a lot of power raised , but their is a way to do it fastly . Consider the given first ;

[tex]{:\implies \quad \sf \dfrac{2^{30}+2^{29}+2^{28}}{2^{31}+2^{30}+2^{29}}}[/tex]

Now , here , if we calculate 2³⁰ and the other stuff and then plus and then divide by the stuff in denominator , it will be very long .But here the interesting thing is that , we can see here 28 is the smallest in all powers in both numerator and denominator , but their isn't any 28 raised to 2 in denominator but their is 29 raised to 2 . So , we can take 2 raised to 28 common and then we can cancel it and then it will be very easy for us to calculate it . So , let's proceed

[tex]{:\implies \quad \sf \dfrac{2^{28}(2^{2}+2^{1}+1)}{2^{28}(2^{3}+2^{2}+2^{1})}}[/tex]

[tex]{:\implies \quad \sf \dfrac{\cancel{2^{28}}(2^{2}+2+1)}{\cancel{2^{28}}(2^{3}+2^{2}+2)}}[/tex]

[tex]{:\implies \quad \sf \dfrac{2^{2}+2+1}{2^{3}+2^{2}+2}}[/tex]

[tex]{:\implies \quad \sf \dfrac{4+2+1}{8+4+2}}[/tex]

[tex]{:\implies \quad \sf \dfrac{7}{14}=\dfrac12}[/tex]

[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{\dfrac{2^{30}+2^{29}+2^{28}}{2^{31}+2^{30}+2^{29}}=\dfrac12}}}[/tex]

Hence , The required answer is ½

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