Answered

IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Our platform is designed to provide quick and accurate answers to any questions you may have.

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.
Prove △GEC ≅ △HFA.

Given ABCDis A Parallelogram GEC HFA And AE FC Prove GEC HFA class=

Sagot :

[tex]\\ \rm\hookrightarrow AE\cong FC[/tex]

So parallelogram BGAE and HDFC are equal.

  • GE=FC

And

  • BG=HD

As BG=HD

  • GC=AH

Hence

[tex]\\ \rm\hookrightarrow \triangle GEC\cong \triangle HFA(SSA)[/tex]

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.