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"Determine the heat of reaction for the decomposition of one mole of benzene to acetylene
C6H6(1) ► 3C2H2(g)
given the following thermochemical equations:
2C6H6(1) + 1502(g) → 12C02(g) + 6H2O(g))
2C2H2(g) + 502(g) → 4CO2(g) + 2H2O(g)
ΔΗ = -6271 kJ
AH= -2511 kJ
a. 3760 kJ
b. 6902 kJ
c. 8782 kJ
d. 631 kJ
e. 1262 kJ

Sagot :

Adioabiolaidn

The heat of reaction for the decomposition of one mole of benzene to acetylene is; 1631 kJ

Determining Heat of Decomposition

The target reaction as given in the task content is;

  • C6H6(1) ► 3C2H2(g)

The premise reactions can be modified by multiplying the first and second reactions by 1/2 and -3/2 respectively.

Hence, we have hear of reactions;

  • ΔΗ = -2135.5 kJ
  • AH= +3766.5 kJ

Hence, the required heat of reaction for the decomposition is; -2135.5 kJ + 3766.5 kJ = 1631 kJ.

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