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CASE 1

The trainee travels by means of a scooter and is only able to depart his home after sunrise (07:00), due to broken lights . The distance from his house to the training site is 60 km. If he used a car, still departing 07:00, he would travel an average of 30 km/h faster and reach the training site 20 minutes earlier. Take the average speed of the scooter as s.

Use the following variables for each quantity: time = t; average speed = s; distance = d.

Determine:
an expression for the average speed of the car​

Sagot :

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The average speed of the scooter is 60 km/h.

Speed

Speed is the ratio of the total distance to total time. It is given by:

Speed = distance / time

Let s represent the average speed of the scooter and t represent the time. Hence:

s = 60/t

t  = 60/s

For the car:

s + 30 = 60/(t - 1/3)

(s + 30)(60/s - 1/3) = 60

60 - s/3 + 1800/s - 10 = 60

s² + 30s - 5400 = 0

s = 60 km/h

The average speed of the scooter is 60 km/h.

Find out more on Speed at: https://brainly.com/question/4931057

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