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Darren walks at a speed of 5.7 kilometres per hour.
(a) Work out an estimate for the distance, in metres, that Darren walks in 19 minutes.


Sagot :

D= SxT
D= 5.7x19/60= 1.80km (Hope this is correct!)

The total distance walked by Darren in 19 minutes with the speed of 5.7 km/hr 1805 meters.

What is the rate of speed?

The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,

[tex]s=\dfrac{d}{t}[/tex]

Here, (d) is the distance travelled by the object and (t) is time taken but the object to cover that distance.

Darren walks at a speed of 5.7 kilometers per hour. Convert this speed in the meter per second by multiplying it with fraction 5/18.

[tex]s=5.7\times\dfrac{5}{18}\\s=1.5833[/tex]

Now, Darren walks in 19 minutes or in 1140 seconds (19×60) with the speed of 1.5833 m/s. Thus,

[tex]1.5833=\dfrac{d}{1140}\\d=1140\times1.5833\\d\approx1805\rm m[/tex]

Hence, the total distance walked by Darren in 19 minutes with the speed of 5.7 km/hr 1805 meters.

Learn more about the rate of speed here:

https://brainly.com/question/359790