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Find the area of an acute triangle with a base of 13 inches and a height of 5 inches.​

Sagot :

  • Base=B=13in
  • Height=H=5in

Area:-

[tex]\\ \rm\hookrightarrow \dfrac{1}{2}BH[/tex]

[tex]\\ \rm\hookrightarrow \dfrac{1}{2}(13)(5)[/tex]

[tex]\\ \rm\hookrightarrow 65/2[/tex]

[tex]\\ \rm\hookrightarrow 32.5in^2[/tex]

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