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100 grams of iron ore contains 30.06% oxygen find the empirical formula​

Sagot :

Answer: Fe2O3

Explanation:

100 grams of iron ore = 30.06% oxygen

100 - 30.06 = 69.94% iron

Mr of Iron = 55.85

Mr of Oxygen = 16

Iron = 69.94/55.85 = 1.252

Oxygen = 30.06/16 = 1.879

1.879 / 1.252 = 1.5 of Oxygen

1.252/1.252 = 1 of Iron

we can write that as Fe1O1.5 but we can't use decimals therefore we have to multiply the whole thing by 2

So it comes out to be Fe2O3

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