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Sagot :
Answer:
[tex]y=-2x+5[/tex]
Step-by-step explanation:
Slope (m): [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
I will be using (1,3) and (-1,7) to find the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\\\m =\frac{7-3}{-1-1}\\\\m=\frac{4}{-2}\\\\m=-2[/tex]
[tex]y=mx+b[/tex]
[tex]y=-2x+b[/tex]
(1,3)
[tex]y=-2x+b\\3=-2(1)+b\\3=-2+b\\+2 +2\\5=b[/tex]
[tex]y=-2x+5[/tex]
Hope this helps!
Answer:
y = -2.4x + 5
Step-by-step explanation:
Note that the y-intercept is (0, 5).
Thus, the framework y = ?x + ? becomes y = ax + 5.
The x-intercept is (2.5, 0), as seen in the graph. b = 0. Then, y = ax + 5 becomes
0 = a(2.5) + 5, which in turn becomes 2.5a = -5.
Solving for the coefficient a, we get a = -5/2.5, or a = -2, and the equation of the line is thus
y = -2x + 5
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