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100 POINTS PLUS BRAINLIST

100 POINTS PLUS BRAINLIST class=

Sagot :

  • tanB=tanY
  • cosB=cosY
  • sinB=sinY

[tex]\\ \rm\hookrightarrow sinY=\dfrac{P}{H}=\dfrac{9.6}{29.6}=0.32[/tex]

[tex]\\ \rm\hookrightarrow cosY=\dfrac{B}{H}=\dfrac{28}{29.6}=0.94[/tex]

[tex]\\ \rm\hookrightarrow tanY=sinY/cosY=0.34[/tex]

Semsee45idn

Answer:

[tex]\sf \tan B=0.34[/tex]

[tex]\sf \cos B=0.95[/tex]

[tex]\sf \sin B=0.32[/tex]

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

  • [tex]\theta[/tex] is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

If ΔXYZ ~ ΔACB then ∠B = ∠Y

From inspection of ΔXYZ:

  • [tex]\theta[/tex] = Y
  • O = XZ = 9.6
  • A = XY = 28
  • H = ZY = 29.6

[tex]\sf \implies \tan B = \tan Y = \dfrac{9.6}{28}=0.34[/tex]

[tex]\sf \implies \cos B = \cos Y = \dfrac{28}{29.6}=0.95[/tex]

[tex]\sf \implies \sin B = \sin Y = \dfrac{9.6}{29.6}=0.32[/tex]

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