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A person invested $710 in an account growing at a rate allowing the money to double every 12 years. How long, to the nearest tenth of a year would it take for the value of the account to reach $980?

Sagot :

Compound interest is the adding of interest to the principle sum of a loan or deposit. The time it will take the account to reach $980 is 5.6 years.

What is compound interest?

Compound interest is the adding of interest to the principle sum of a loan or deposit. It's the outcome of reinvesting interest rather than paying it out, so that interest is received on the principal plus previously collected interest in the next quarter.,

[tex]A = P(1+ \dfrac{r}{n})^{nt}[/tex]

where A is the final amount

P is the principal amount

r is the rate of interest

n is the number of times interest is charged in a year

t is the number of years

Given the initial amount in the account was $710, while the rate of interest is such that money doubles itself in 12 years. Therefore, the rate will be,

2(710) = 710(1+x)¹²

2 = (1+x)¹²

Taking log,

log₍ₓ₊₁₎2 = 12

(log 2) / log(x+1) = 12

(log 2)/12 = log(x+1)

0.025 = log (x+1)

Taking antilog,

1.059463 = x+ 1

x = 0.05946 = 5.9463%

Now, the time it will take the account to reach $980 is,

980 = 710(1+5.9463%)ⁿ

Taking Log,

[tex]\log_{1.059463}1.38 =n\\\\n = \dfrac{\log 1.38}{\log 1.059463}\\[/tex]

n = 5.57956 ≈ 5.6 years

Hence, the time it will take the account to reach $980 is 5.6 years.

Learn more about Compound Interest:

https://brainly.com/question/25857212

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