Answer:
Don't agree with Diego.
Step-by-step explanation:
When x=5,
[tex]10 + {x}^{2} = 10 + {5}^{2} = 35 \\ {2}^{x} = {2}^{5} = 32[/tex]
35>32
When x=6,
[tex]10 + {x}^{2} = 10 + {6}^{2} = 46 \\ {2}^{x} = {2}^{6} = 64[/tex]
Obviously, 46<64
When x=7,
[tex]10 + {x}^{2} = 10 + {7}^{2} = 59 \\ {2}^{x} = {2}^{7} = 128[/tex]
Obviously, 59<128
Hence, conclusion
When
[tex]x \geqslant 6[/tex]
[tex]10 + {x}^{2} \leqslant {2}^{x} [/tex]
