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how many grams of NaCl will be produced from 4.67g of FeCl3 in the following reaction? FeCl3+3NaOH -> Fe(OH)3 + 3NaCl

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Answer:

mass of NaCl: 5.0436 g

Explanation:

  • balanced equation: FeCl₃+3NaOH -> Fe(OH)₃ + 3NaCl

Given:

  • 4.67g of FeCl₃
  • FeCl₃ molar mass is 162.5 g

solve for moles of FeCl₃

moles = mass/mr

moles = 4.67/162.5

moles = 0.0287

solve for moles of NaCl using molar ratio

FeCl₃ : 3NaCl

1 : 3

0.0288 : 0.0862

Then find mass:

  • molar mass of NaCl is 58.5

mass = moles * Mr

mass = 0.0862 * 58.5

mass = 5.0436 g
  • 1mol of FeCl_3 produces 3mols of NaCl.

Moles of FeCl3

[tex]\\ \rm\hookrightarrow \dfrac{4.67}{162.5}=0.03mol[/tex]

Now

  • moles of NaCl=0.03(3)=0.09mol

Mass of NaCl

  • 0.09(58.5)=5.265g
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