Answered

IDNLearn.com is your go-to resource for finding expert answers and community support. Discover comprehensive answers to your questions from our community of knowledgeable experts.

please help me.. i would appreciate it.. 50 points and will mark brainliest

Please Help Me I Would Appreciate It 50 Points And Will Mark Brainliest class=

Sagot :

RilakkuOatsidn
Answer: The mass of Cu produced is 4.88 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ……(1)

Given mass of aluminum = 2.98 g

Molar mass of aluminum = 27 g/mol

Plugging values in equation 1:

\text{Moles of aluminum}=\frac{2.98g}{27g/mol}=0.1104 mol

The given chemical equation follows:

2Al(s)+3CuSO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3Cu(s)

By the stoichiometry of the reaction:

If 2 moles of aluminum produces 3 moles of Cu

So, 0.1104 moles aluminium will produce = \frac{3}{2}\times 0.1104=0.1656mol of Cu

Molar mass of Cu = 63.5 g/mol

Plugging values in equation 1:

\text{Mass of Cu}=(0.1656mol\times 63.5g/mol)=10.516g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ……(2)

Given values:

% yield of product = 46.4 %

Theoretical value of the product = 10.516 g

Plugging values in equation 2, we get:

46.4=\frac{\text{Actual value of Cu}}{10.516g}\times 100\\\\\text{Actual value of Cu}=\frac{46.4\times 10.516}{100}\\\\\text{Actual value of Cu}=4.88g

Hence, the mass of Cu produced is 4.88 g
Indrawboyidn

2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu

mole Al = 2.57 : 27 g/mole = 0.095

mole Cu = 3/2 x mole Al = 3/2 x 0.095 = 0.143

mass Cu (theoretical) = 0.143 x molar mass Cu = 0.143 x 63.5 g/mole = 9.08 g

mass Cu produced (actual, 56.9% yield) = 56.9% x 9.08 g = 5.17 g

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.