Denniswalker510idn
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1. A contractor applies for two contracts:
A - building a school workshop and B - building a school library.
The probability of getting contract A is 0.6. The probability of getting contract B depends on whether or not A is obtained and is 0.7 if A is obtained but only 0.4 if A is not obtained. What is the probability of getting atleast one contract?​

Sagot :

Answer:

0.76

Step-by-step explanation:

[tex]There\ are\ two\ situations:\ 1.\ A\ is\ obtained\[/tex]
                                            [tex]2.\ A\ is\ not\ obtained\ but\ B\ is\ obtained\[/tex]

[tex]1:P=0.6[/tex]

[tex]2:P=(1-0.6)[/tex] × [tex]0.4=0.16[/tex]

So the probability is [tex]ab+0.16=0.76[/tex]

I hope this helps you

:)

Probability helps us to know the chances of an event occurring. The probability of getting at least one contract is 0.76.

What is Probability?

Probability helps us to know the chances of an event occurring. The sum of all the probabilities of an event is always equal to 1. The formula for probability is given as,

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

The probability of not getting A, A' = 1 - 0.6 = 0.4

The probability of not getting B, when contractor does not get A,

A'∩B' = 1 - 0.4 = 0.6

Now, the probability of not getting any of the contract is,

Probability of not getting any contract = P(A') × P(A'∩B')

                                                                = 0.4 × 0.6

                                                                = 0.24

Now, the probability of getting at least one contract is,

Probability of getting at least one contract

= Total Probability - P(A'∩B')

= 1 - 0.24

= 0.76

Hence, the probability of getting at least one contract is 0.76.

Learn more about Probability here:

https://brainly.com/question/795909

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