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BRAINLIEST :
In this rectangle, the length is 4 cm more than the width. The perimeter is 14cm. Find the value of 'x’

Sagot :

Lakshmikatta883idn

Area=45 cm2

Explanation:

Let the length be L

and the width be W (with all measurements in cm.)

We are told that L=W+4

and

that the perimeter is 28

Since the perimeter of a rectangle is 2(L+W)

we have

XXX2(L+W)=28

XXX2(W+4+W)=28

XXX2(2W+4)=28

XXX(2W+4)=14

XXX2W=10

XXXW=5

and since L=W+4

XXXL=9

Finally

XXXArea=L×W=9×5=45 (sq.cm

ItzStarzMeidn

Answer :

  • Value of x is 1.5 cm

Explaination :

In the question it is given that the length is 4 cm more than the width so let us assume the width as x.

Therefore,

  • Length (l) = 4 + x
  • Breadth = x

As we know the formula of calculating the perimeter of rectangle is,

  • P = 2 (l + b)

Here,

  • P is perimeter
  • l is length
  • b is breadth

Putting their respective values,

=> 14 = 2 (x + 4 + x)

=> 14 = 2 × (x + 4 + x)

=> 14 = 2x + 8 + 2x

=> 14 = 4x + 8

=> 14 - 8 = 4x

=> 4x = 6

=> x = 6 / 4

=> x = 3 / 2

=> x = 1.5

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