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Sagot :
Answer:
A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day
Answer:
QUESTION
✍Find the speed of a satellite in geostationary orbit.
☛Answer☚
This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day.
➽bʀᴀɪɴʟɪᴇsᴛ➽
A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day
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reminder my answer is. Based on what I understood pls mark me brainliest thanks
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correct my answer in case it is wrong
#would have helped
#Carry on Learning
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