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Abby used the quadratic formula to find the zeros of the function below. However, Abby made a mistake. What mistake did Abby make

PLEASE HELP Abby Used The Quadratic Formula To Find The Zeros Of The Function Below However Abby Made A Mistake What Mistake Did Abby Make class=

Sagot :

The mistake made by Abby in solving the quadratic equation was at Step 2, in which she did not simplify her answer correctly.

What is the solution of a quadratic equation?

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The solutions are given by:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

In this problem, Abby substituted correctly, but at the simplification, she made a mistake in the signal, as:

[tex](-6)^2 - 4(5)(-8) = 36 + 160[/tex]

Hence the mistake was in Step 2.

More can be learned about quadratic equations at https://brainly.com/question/24737967

Raphealnwobiidn

Step 2 is not correct, she did not simplify under the square root correctly.

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the equation:

5x² - 6x - 8 = 0

a = 5, b = -6 and c = -8

From the equation:

[tex]x=\frac{-b \pm \sqrt{b^2-4ac} }{2a} \\\\Step\ 1:x=\frac{-(-6) \pm \sqrt{(-6)^2-4(5)(-8)} }{2(5)} \\\\Step\ 2:x=\frac{6\pm \sqrt{36+160} }{10}\\\\Step\ 3: x=-0.8\ AND\ x=2[/tex]

Step 2 is not correct, she did not simplify under the square root correctly.

find out more on equation at: https://brainly.com/question/2972832

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