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it’s number 11. find the value of x to the nearest tenth. please help thank you!

Its Number 11 Find The Value Of X To The Nearest Tenth Please Help Thank You class=

Sagot :

Answer:

d

Step-by-step explanation:

using the tangent ration in the left- side right triangle

tan56 = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{115}{y}[/tex] ( y represents the adjacent side )

multiply both sides by y

y × tan56° = 115 ( divide both sides by tan56° )

y = [tex]\frac{115}{tan56}[/tex] ≈ 77.6

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using the tangent ratio in the large outer right triangle

tan35° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{115}{x+y}[/tex] ( multiply both sides by x + y )

(x + y) × tan35° = 115 ( divide both sides by tan35° )

x + y = [tex]\frac{115}{tan35}[/tex] ≈ 164.2

then

x + 77.6 = 164.2 ( subtract 77.6 from both sides )

x = 86.6

Devishri1977idn

Answer:

Step-by-step explanation:

[tex]tan \ 56 =\dfrac{opposite \ side }{adjacent \ side}\\\\\\1.4825=\dfrac{115}{y}\\\\y=\dfrac{115}{1.4825}\\\\\\[/tex]

y = 77.6

[tex]tan \ 35 =\dfrac{115}{x+77.6}\\\\0.7*(x +77.6) =115\\\\x + 77.6 =\dfrac{115}{0.7}\\\\[/tex]

x + 77 .57 = 164.2

x = 164.2 - 77.6

x = 86.6

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