Discover how IDNLearn.com can help you find the answers you need quickly and easily. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.
Determine the empirical formula for a compound containing 85.6 g of carbon and 14.4 g of hydrogen. Please show work
take gram & convert to mol (using the mm of the element) ,
85.6g C [tex]\frac{1 mol }{12.01g}[/tex] = 7.12 14.4g H[tex]\frac{1 mol}{1.01g}[/tex] =14.2 then take the smallest number & divide 7.12/7.12 =1 14.2/7.12= 2. since the numbers are in whole numbers the answer is [tex]C_{1}H_{2}[/tex].
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
