Answer: See below
Explanation:
C3H8 + 502 ----> 3CO2 + 4H2O
1 mol of C₃H₈ reacts to 5 moles of oxygen, in a combustion reaction in order to produce 3 moles of carbon dioxide and 4 moles of water.
First of all, we need to know the limiting reagent:
4.71 g * 1mol / 44g = 0.107 moles of C₃H₈
4.13 g * 1mol/ 32g = 0.129 moles of oxygen
1 mol of C₃H₈ can react to 5 moles of O₂
Then, O moles, must react to (0.107 * 5) /1 = 0.535 moles.
We only have 0.129 moles of O₂ and we need 0.535 moles. We do not have enough oxygen, so it's the limiting reagent.
5 moles of oxygen can produce 3 moles of CO₂
0.129 moles can produce (0.129 * 3) /5 = 0.0774 moles.
Convert the moles to mass : 0.0774 mol * 44g /mol = 3.4056g
Therefore, the maximum mass of CO2 that can be formed is 3.4056g
