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If a town with a population of 10,000 doubles in size every 17 years. What will the population be 68 years from now?

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Linandrew41idn

Let us set up the equation:

[tex]total population = 10000*(2)^{68/17}=10000*(2^4)=160000[/tex] people

  • 10000 is the initial population
  • 2 is the rate at which the population grows
  • 68/17 is the number of periods that the population grows

Hope that helps!

Abiolataiwo2015idn

Assuming a town with a population of 10,000 doubles in size every 17 years. The population  68 years from now is 160,000.

Population

P(t) = 10000×2t/12

Where:

t=time;  k is a constant

P(68) = 10000×2^68/12

P(68) = 10000×2^4

P(68) = 10000×16

P(68) = 160,000

Inconclusion assuming a town with a population of 10,000 doubles in size every 17 years. The population  68 years from now is 160,000.

Learn more about population here:https://brainly.com/question/25630111

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