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Sagot :
The probability that the team with the home advantage wins the series is 2P - 3P² + 2P³.
How to calculate the probability?
From the information given, the home team wins with probability p > 1/2.
Therefore, losing a game at home is given has probability 1-P. Similarly, winning the home team in a game at away probability will be 1-P.
Therefore, the probability that the team with the home advantage wins the series will be:
P(T) = P(1 - P) + (P × P × P) + (1 - P)(1 - P)(P)
= P - P² + P³ + (P - 2P² + P³)
= 2P - 3P² + 2P³
In conclusion, the probability is 2P - 3P² + 2P³.
Learn more about probability on:
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