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Sagot :
slope of parallel line: 2
y = 2x + b
1 = 2(6) + b
1 = 12 + b
b = -11
equation of parallel line: y = 2x -11
Solution:
Since the original line is parallel to y = 2x + 5, the original line's slope must be 2.
Using point slope form:
- y - y₁ = m(x - x₁)
- => y - 1 = 2(x - 6)
- => y - 1 = 2x - 12
- => y = 2x - 11
The equation of a line that is parallel to y = 2x + 5 and goes through the point (6, 1) is y = 2x - 11.
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