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The measure of m<CBD is 63 degrees

Circle Geometry

According to line geometry, the sum of angles on a straight line is expressed as:

arcCD + m<CBF = 180

Given that

arcCD= 5x + 3 and;

m<CBF = 11x - 15

Substitute

5x + 3 + 11x - 15 = 180

16x - 12 = 180

16x = 192

x = 12

Determine the measure of m<CBD

m<CBD = arc CD = 5x + 3

m<CBD = 5(12) + 3

m<CBD = 63 degrees

Hence the measure of m<CBD is 63 degrees

Learn more on circle geometry here; https://brainly.com/question/24375372

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