Answered

From beginner to expert, IDNLearn.com has answers for everyone. Ask anything and receive immediate, well-informed answers from our dedicated community of experts.

100 points! please help me will mark brainliest

100 Points Please Help Me Will Mark Brainliest class=

Sagot :

S + O2 → SO2

Moles of S:

11/32.06 = 0.3431 mol

Moles of O2:

44/15.999 = 2.75 mol

Sulfur will be the limiting reagent.

Oxygen will be the excess reagent

2.75 - 0.3431 = 2.4071 mols of oxygen leftover

2.4071 * 15.999 = 38.511

38.511 grams of oxygen will be leftover

Indrawboyidn

Reaction

S + O₂ ⇒ SO₂

mole S = 11 : 32 g/mol = 0.34375

mole O₂ = 44 : 32 g/mol = 1.375

S as a limiting reactant (smaller) and converted all to sulfur dioxide

mole O₂ (unreacted) = 1.375 - 0.34375 = 1.03125

mass O₂ (unreacted) = 1.03125 x 32 = 33 g

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.