Connect with a knowledgeable community and get your questions answered on IDNLearn.com. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.
Sagot :
Are produced 72 grams of water in this reaction.
Mole calculation
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:
[tex]Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2[/tex]
Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:
[tex]MM_{Ca(OH)_2} = 74.1g/mol[/tex]
[tex]MM = \frac{g}{mol}[/tex]
[tex]74.1 = \frac{35.8}{mol}\\mol = 2[/tex]
So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O
[tex]\frac{1mol}{2mol} =\frac{2mol}{xmol}[/tex]
[tex]x = 4mol[/tex]
Finally, just find the number of grams of water using your molar mass:
[tex]MM_{H_2O} = 18g/mol[/tex]
[tex]18= \frac{m}{4}\\m = 72g[/tex]
So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.