Discover new information and get your questions answered with IDNLearn.com. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.
Sagot :
Are produced 72 grams of water in this reaction.
Mole calculation
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:
[tex]Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2[/tex]
Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:
[tex]MM_{Ca(OH)_2} = 74.1g/mol[/tex]
[tex]MM = \frac{g}{mol}[/tex]
[tex]74.1 = \frac{35.8}{mol}\\mol = 2[/tex]
So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O
[tex]\frac{1mol}{2mol} =\frac{2mol}{xmol}[/tex]
[tex]x = 4mol[/tex]
Finally, just find the number of grams of water using your molar mass:
[tex]MM_{H_2O} = 18g/mol[/tex]
[tex]18= \frac{m}{4}\\m = 72g[/tex]
So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.
