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If (− 4, −8) and (−10, −12) are the endpoints of a diameter of a circle, what is the equation of the circle?

Sagot :

Answer:

(x + 7)² + (y + 10)² =13

Step-by-step explanation:

Center is at ((-4) + (-10))/2, ((-8) + (-12))/2) = (-7, -10)

distance between two pints = Diameter = [tex]\sqrt{[(-10) - (-4)]^2+ [(-8) - (-12)]^2}=\sqrt{6^2+4^2}=2\sqrt{13}[/tex]

Radius = [tex]\sqrt{13}[/tex]

so the equation is

(x + 7)² + (y + 10)² = 13

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