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A solution was made by dissolving 800. 0 g of NaOH in 25,200 g of water. Calculate the morality, molality, and mole fraction of NaOH

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The morality, molality, and mole fraction of NaOH is mathematically given as

  1. morality= 4 ppm
  2. molality=0.7936m
  3. x1 = 0.152

What are the morality, molality, and mole fraction of NaOH?

Question Parameters:

A solution was made by dissolving 800. 0 g of NaOH in 25,200 g of water.

Generally, the equation for the Molality   is mathematically given as

molality = (mass / molar mass) x (1/ weight of solvent kg)

Therefore

M= (800 /40) x (1 /25.2)

M=0.7936m

Therefore

m= 10 x 18 / 1000

m= 0.18

Hence

x1 = 0.18 - 0.18 x1

1.18 x1 = 0.18

x1 = 0.152

Where the mole fraction is x1 = 0.152 The mass is

m= (800 / 800 + 2000) x 1000

m= 28.57 %

Hence the morality

molality = mg /L

molality= 8000 x 10^-3 / 2 L

morality= 4 ppm

In conclusion, the morality, molality, and mole fraction of NaOH are given respectively as

morality= 4 ppm

molality=0.7936m

x1 = 0.152

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