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If you combine 390.0 mL of water at 25.00 ∘C and 100.0 mL of water at 95.00 ∘C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Sagot :

103.0 mL because if u calculate the mL of water you realize
Indrawboyidn

heat water 1 = heat water 2

mass of water = density x volume

because density = 1 g/ml then:

mass water 1 = 100 g

mass water 2= 390 g

Input the equation:

mcΔt 1 = mcΔt 2

100 . c . (95 - T) = 390 . c . (T - 25)

9500 - 100T = 390T - 9750

9500+9750 = 390T+100T

19250=490T

T=39.29 °C

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