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Sagot :
Step-by-step explanation:
c= 31.4
c= πD
D= C/π
D= 31.4/3.14 = 10 yards
Answer:-
[tex]\longrightarrow[/tex] 10 yards
Given :-
[tex]\red{\leadsto}\:[/tex][tex]\textsf{Circumference \:of \:the \:circle} [/tex][tex]\sf= 31.4 \:yards [/tex]
Solution:-
[tex]\green{ \underline { \boxed{ \sf{Circumference \: of \: the \: circle = 2πr}}}}[/tex]
- r is radius of circle
[tex]\begin{gathered}\\\implies\quad \sf Circumference \:of \: the \: circle = 31.4 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf 2πr= 31.4 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf 2\times 3.14 \times r= 31.4 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf 6.28 \times r= 31.4 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf r= \frac{31.4}{6.28} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf r= 5 \:yards \\\end{gathered} [/tex]
[tex]\green{ \underline { \boxed{ \sf{Diameter = 2 \times radius }}}}[/tex]
[tex]\begin{gathered}\\\implies\quad \sf Diameter = 2\times 5\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Diameter = 10 \: yards\\\end{gathered} [/tex]
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