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Answer:
Propane burns in air according to the following equation:
C
3
H
8
+5O
2
→3CO
2
+4H
2
O.
1 mole of propane combines with 5 moles of oxygen.
Volume is directly proportional to the number of moles.
1 cm
3
of propane will combine with 5 cm
3
of oxygen.
Only 20% of air contains oxygen. So 1000 cm
3
of air contains 1000cm
3
×
100
20
=200cm
3
of oxygen.
The volume of propane that is consumed on using 1000 cm
3
of air is
5
200cm
3
=40cm
3
.
Reaction
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Avogadro: at the same T and P, the ratio of gas volume = the ratio of gas moles
volume of CO₂ = 3/1 x 25 = 75 m³