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You are wrapping a birthday gift that is packaged in a specially made pyramid-shaped box. The base of the box measures 10 inches by 10 inches and the slant height is 6 inches. How much paper do you need to wrap the box?

Sagot :

Ayden9574idn

Answer:

2 1/4

Step-by-step explanation:

The amount of paper needed to wrap the considered box which has dimension of 10 by 10 by 6 inches is 440 sq. inches

What is the surface area of cuboid?

Let the three dimensions(height, length, width) be x, y,z units respectively.

The surface area of the cuboid is given by

[tex]S = 2(a\times b + b\times c + c\times a)[/tex]

A box is usually in shape of a cuboid.

For this case, its dimensions are 10 inches, 10 inches, and 6 inches.

The amount of wrapper we need is approx same as the area of its surface (assuming we're going to measure the paper needed in terms of its area).

Thus, we get:

Amount of the paper we need to wrap the considered box = surface area of that box = surface area of cuboid of dimension 10 inch by 10 inch by 6 inches = S (say), then:

[tex]S = 2(10\times 10+ 10\times 6 + 6\times 10)\\S = 440[/tex](in sq. inches)

Thus, the amount of paper needed to wrap the considered box which has dimension of 10 by 10 by 6 inches is 440 sq. inches

Learn more about surface area of cuboid here:

https://brainly.com/question/13522634

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