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6.How many moles of gas would be in contained in a 11.2 L container that is at a
pressure of 0.75 atm and 300 K?
A.0.17
B.034
C.1.37
D.7.31


Sagot :

0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

HOW TO CALCULATE NUMBER OF MOLES?

The number of moles of a substance can be calculated using the following expression:

PV = nRT

Where;

  • p = pressure (atm)
  • v = volume (L)
  • n = number of moles
  • R = gas law constant
  • T = temperature

0.75 × 11.2 = n × 0.0821 × 300

8.4 = 24.63n

n = 8.4 ÷ 24.63

n = 0.34 moles

Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

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