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Your class is having a class picture taken on the lawn. The photographer is positioned 14 feet away from the center of the class. The photographer turns 50° to look at either end of the class.



a. What is the distance between the ends of the class? Round your answer to the nearest tenth.
The distance is about
feet.

b. The photographer turns another 10° either way to see the end of the camera range. If each student needs 2 feet of space, about how many more students can fit at the end of each row? Explain. Round answers to the nearest tenth when necessary.
About
more students can fit at the end of each row. The triangle formed by the
° angle has an opposite leg that is about
feet longer than the opposite leg of the triangle formed by the
° angle. Because each student needs 2 feet of space,
more students can fit on each end with about
feet of space left over.

Sagot :

GalaxyPrincess22idn

Answer:

your answer is b. The photographer turns another 10° either way to see the end of the camera range. If each student needs 2 feet of space, about how many more students can fit at the end of each row? Explain. Round answers to the nearest tenth when necessary.

About

more students can fit at the end of each row. The triangle formed by the

° angle has an opposite leg that is about

feet longer than the opposite leg of the triangle formed by the

° angle. Because each student needs 2 feet of space,

more students can fit on each end with about

feet of space left over.

Step-by-step explanation:

Yangjinrui9296idn

Answer:

a) 33.4

b) About 3 students can fit at the end of each row. The triangle formed by the 60° angle has an opposite leg of that is about 7.5 feet longer than the opposite leg formed by the 50° angle. Because each students needs 2 feet of space, 3 more students can fit on each end with about 1.5 feet of space left over.

Step-by-step explanation:

A. I used the Tangent ratio which is opposite/adjacent

tan(50)=x/14

14*tan(50)=x

*Use you calculators here and you should get about 16.68, but this is only one of the right triangle, so multiply that by 2 and you should get about 33.36 which rounded should become 33.4

B. For the amount of students you can fit at the end of each row, you need to find how long the opposite leg of the 60° triangle is than the opposite leg of the 50° triangle. to do this use the tangent ratio

since the 60° triangle is a special triangle, the opposite side is 14√3

14√3 - (14 · tan(50) ≈ 7.56  ← the answer is 7.5 probably since they didn't round (in Big Ideas)

7.56/2 ≈ 3.78 ← 2 feet of space for each student

↑answer is just 3 since you cannot split living objects

The last answer is 1.5

the get the left over amount, we would have to take the length opposite leg of the 60° triangle and divide it by the length of the opposite leg of the 50° triangle

14√3 ÷ (14 · tan(50) ≈ 1.45 ← must use parentheses otherwise they will divide your answer by 14 and then multiply, which none of us wants.

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