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The product of these two expressions 3y⁻⁴ and 2y⁻⁴ is 6/y⁸. Then the correct option is A.
It is also known as the product. If the object n is given to m times then we just simply multiply them.
The expressions are as 3y⁻⁴ and 2y⁻⁴.
The product of these two will be
[tex]\rm 3y^{-4} * 2y^{-4}\\\\3*2*y^{-4}*y^{-4}\\\\6*y^{-4-4}\\\\6*y^{-8}\\\\\dfrac{6}{y^{8}}[/tex]
The product of these two expressions 3y⁻⁴ and 2y⁻⁴ is 6/y⁸. Then the correct option is A.
More about the multiplication link is given below.
https://brainly.com/question/19943359
The result of the product expression [tex](3y ^{-4}) (2y^{-4})[/tex] is 6/y^8
The product expression is given as:
(3y ^{-4}) (2y^{-4)
Rewrite the expression properly as:
[tex](3y ^{-4}) (2y^{-4})[/tex]
Rewrite the factors of the expression as fractions
[tex]\frac{3}{y ^4} * \frac{2}{y^4}[/tex]
Multiply 3 and 2
[tex]\frac{6}{y ^4*y^4}[/tex]
Apply the law of indices
[tex]\frac{6}{y ^{4+4}}[/tex]
Add 4 and 4
[tex]\frac{6}{y ^{8}}[/tex]
Hence, the product of [tex](3y ^{-4}) (2y^{-4})[/tex] is [tex]\frac{6}{y ^{8}}[/tex]
Read more about products at:
https://brainly.com/question/10873737