Answer:
In order:
[tex]\frac{16}{k^2}[/tex]
[tex]180c^{17}d^7[/tex]
[tex]-\frac{27y^4}{x^2}[/tex]
Step-by-step explanation:
[tex]48k^5/3k^7\\\\\frac{48k^5}{3k^7} \\\\\frac{16}{k^{7-5}} \\\\\frac{16}{k^2}[/tex]
[tex]12c^7d^4*15c^{10}d^3\\\\12*15c^{7+10}d^{4+3}\\\\180c^{17}d^7[/tex]
[tex](-xy)^4 *(-3x^{-2})^3\\\\x^4y^4*(-3x^{-2})^3\\\\x^4y^4*-27x^{-6}\\\\-27x^{-6+4}y^4\\\\-27x^{-2}y^4\\\\-27*\frac{1}{x^2} *y^4\\\\-\frac{27y^4}{x^2}[/tex]
Hope this helps!
