Dive into the world of knowledge and get your queries resolved at IDNLearn.com. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.
Sagot :
Answer:
Explanation:
Balanced equation :
2NaOH (aq) + Mg(NO3)2 (aq) → Mg(OH)2(s) + 2NaNO3(aq)
2 mole NaOH reacts with 1 mole Mg(NO3)2 to produce 1 mole Mg(OH)2.
Check for limiting reactant :
Mol NaOH in 200.0 mL of 0.125 M solution
Mol = 0.125 mol/L * 200 mL / 1000 mL/L = 0.025 mol
This will react with 0.025 / 2 = 0.0125 mol Mg(NO3)2
Mol Mg(NO3)2 in 400 mL of 0.025 M solution
= 400 mL / 1000 mL/L * 0.025 mol /L = 0.01 mol Mg(NO3)2
The NaOH is in excess and the limiting reactant is Mg(NO3)2
0.01 mol Mg(NO3)2 will produce 0.01 mol Mg(OH)2
Molar mass Mg(OH)2 = 58.32 g/mol
Mass of 0.01 mol Mg(OH)2 = 0.01mol * 58.32 g/mol = 0.5832 g
Product isolated was 0.45 g
Percent yield = Product / Reactant * 100%
= 0.45 / 0.5832 * 100%
= 77.16% yield.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.
