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The school drama club sold 2,400 tickets to a play and made $9,000 from the ticket sales. Student tickets,
X, were $3 and adult tickets, y, were $5.
Create a system of two equations to represent this situation.

Sagot :

Azailiaidn

Hi!

Given:

  • total tickets = 2,400
  • total profit = 9,000
  • student tickets cost $3
  • adult tickets cost $5
  • x = student tickets
  • y = adult tickets

The first equation we can make can use the total number of tickets. The total number of tickets would be equal to the number of student tickets plus the number of adult tickets, correct? Therefore:

[tex]x+y=2400[/tex]

Now, the second one can use the profit and the price of each ticket. The number of student tickets multiplied by 3 (for the price) plus the number of adult tickets multiplied by 5 would be equal to the total profit. Hence:

[tex]3x+5y=9000[/tex]

Therefore, your system of equations is:

[tex]x+y=2400[/tex]

[tex]3x+5y=9000[/tex]

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