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Answer:
(x-3)(x+3)
Step-by-step explanation:
We are given the expression [tex]\displaystyle \large{x^2-9}[/tex]:—
To factor this expression, we have a formula for it which is difference of two squares:—
[tex]\displaystyle \large{a^2-b^2=(a+b)(a-b)}[/tex]
You can also swap from [tex]\displaystyle \large{(a+b)(a-b)}[/tex] to [tex]\displaystyle \large{(a-b)(a+b)}[/tex] via multiplication property.
From the expression, factor using the formula above:—
[tex]\displaystyle \large{x^2-9=(x^2)-(3)^2}\\\displaystyle \large{x^2-9=(x-3)(x+3)}[/tex]
Therefore, the factored expression is:—
[tex]\displaystyle \large{\boxed{(x-3)(x+3)}}[/tex]
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