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A charge of 1. 5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How much potential energy is stored in the capacitor? × 10–5 J.

Sagot :

It is a type capacitor is in which two metal plates arranged in such a way so that they are connected in parallel . The potential energy is stored in the capacitor will be 2.7×10⁻⁵.

What is parallel plate capacitor ?

It is an type capacitor is an in which two metal plates arranged in such a way so that they are connected in parallel and have some distance between them.

A dielectric medium is a must in between these plates. helps to stop the flow of electric current through it due to its non-conductive nature .

The given data in the problem is;

Q is the charge= 1.5 µC

V is the change in voltage across the plates is = 36 V.

U is the potential energy=?

The formula for the potential energy is given by;

[tex]\rm U= \frac{1}{2} \times Q \times V \\\\ \rm U= \frac{1}{2} \times 1.5\times 10^{-6} \times 36 \\\\ \rm U=2.7\times10^{-5}[/tex]

Hence the potential energy is stored in the capacitor will be 2.7×10⁻⁵.

To learn more about the parallel plate capacitor refer to the link;

https://brainly.com/question/12883102