Answered

IDNLearn.com is designed to help you find reliable answers quickly and easily. Ask your questions and receive comprehensive and trustworthy answers from our experienced community of professionals.

(6.) The point A(-5,12) lies on the circle whose equation is x + y2 = 169. What is the secant of
an angle drawn in standard position whose terminal rays passes through A?

Sagot :

Oladayoademosuidn

The secant of the angle through a point (-5, 3) is -13/5  

Equation of a circle

The equation of a circle with center (0,0) is given by

x² + y² = r² where r = radius of circle

Now, comparing this to the equation of the given circle x² + y² = 169,

⇒ r² = 169

r = √169

r = 13

Secant of angle

The secant of the angle through a point (x, y) is secФ = r/x where

  • r = radius of circle and
  • x = x-coordinate of point

Now for the point A(-5,12), x = -5.

Since r = 13

secФ = r/x

= 13/-5

= -13/5  

So, The secant of the angle through a point (-5, 3) is -13/5  

Learn more about secant of an angle here:

https://brainly.com/question/14910565

Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.