Find expert advice and community support for all your questions on IDNLearn.com. Get step-by-step guidance for all your technical questions from our dedicated community members.
Sagot :
1: 3x+2y=23
2: 1/2x-4=y
We have that y=1/2x-4 in 2
So lets substitu y in 1
3x+2(1/2x-4)=23
3x+x-8=23
4x=23+8
4x=31
X = 7,75
Now lets replace x in 2:
1/2.7,75-4=y
3,875-4 + y
Y= - 0,125
So (x;y)=(7,75;-0.125)
2: 1/2x-4=y
We have that y=1/2x-4 in 2
So lets substitu y in 1
3x+2(1/2x-4)=23
3x+x-8=23
4x=23+8
4x=31
X = 7,75
Now lets replace x in 2:
1/2.7,75-4=y
3,875-4 + y
Y= - 0,125
So (x;y)=(7,75;-0.125)
[tex]\left\{\begin{array}{ccc}3x+2y=23&(1)\\y=\frac{1}{2}x-4&(2)\end{array}\right\\\\subtitute\ (2)\ to\ (1)\\\\3x+2(\frac{1}{2}x-4)=23\\3x+x-8=23\\4x-8=23\ \ \ \ |add\ 8\ to\ both\ sides\\4x=31\ \ \ \ \ |divide\ both\ sides\ by\ 4\\\boxed{x=7.75}\\\\subtitute\ the\ value\ of\ "x"\ to\ (2)\\\\y=\frac{1}{2}(7.75)-4\\y=3.875-4\\\boxed{y=-0.125}\\\\Answer:\boxed{ \left\[\begin{array}{ccc}x=7.75\ (7\frac{3}{4})\\\\y=-0.125\ (-\frac{1}{8})\end{array}\right}[/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.
