Find expert answers and community-driven knowledge on IDNLearn.com. Our experts are ready to provide prompt and detailed answers to any questions you may have.
Sagot :
The Molecular Mass for Phosphorus is 31 grames / mole.
So, 31g. P.....................1 mole
2.3g. P ..........................x mole
[tex]x= \frac{2,3}{31} = \boxed {0,07} \hbox { moles }[/tex]
So, 31g. P.....................1 mole
2.3g. P ..........................x mole
[tex]x= \frac{2,3}{31} = \boxed {0,07} \hbox { moles }[/tex]
1.Molar mass of phos.=30.97g/mol
2.n=m/M
=2.3g/30.97g/mol
=0.07mol
3. therefore the amount of moles in 2.3g of phosphorus is 0.07mol
2.n=m/M
=2.3g/30.97g/mol
=0.07mol
3. therefore the amount of moles in 2.3g of phosphorus is 0.07mol
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.