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Sagot :
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Consider the number as x
let's solve ~
[tex]\qquad \sf \dashrightarrow \:6(x + 20) = 26[/tex]
[tex]\qquad \sf \dashrightarrow \:6x + 120 = 26[/tex]
[tex]\qquad \sf \dashrightarrow \:6x = - 120 + 26[/tex]
[tex]\qquad \sf \dashrightarrow \:6x = -94[/tex]
[tex]\qquad \sf \dashrightarrow \:x = - 94 \div 6[/tex]
[tex]\qquad \sf \dashrightarrow \:x = \dfrac{ - 47}{3} [/tex]
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Answer:
[tex](x + 20) 6 = 26[/tex]
[tex]6x + 120 = 26[/tex]
[tex]6x = 26 - 120[/tex]
[tex]6x = - 94[/tex]
[tex] \displaystyle \: x = \frac{ - 94}{6} [/tex]
[tex] \displaystyle{x = \frac{ - 47}{3} }[/tex]
[tex]\red {\rule{35pt}{2pt}} \green{ \rule{35pt}{2pt}}\orange{ \rule{35pt}{2pt}}\pink{ \rule{35pt}{2pt}}\blue{ \rule{35pt}{2pt}}\purple{ \rule{35pt}{2pt}}\red{ \rule{35pt}{2pt}}[/tex]
[tex] \bold{ \displaystyle{x = - \frac{47}{3} }}[/tex]
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