Answered

Connect with a community that values knowledge and expertise on IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.

A chemist has one solution that is 20% alcohol and another that is 60% alcohol.
How much of each solution must the chemist use to get 200 mL of a solution that is 52%
alcohol?

Sagot :

Col7kingsidn

Answer:

solution 1= 40ml

solution 2= 160ml

Step-by-step explanation:

%alcohol= amount of alcohol/total solutionx100

0.52x200=104ml of alcohol present

0.2x L=0.2Lml of alcohol in solution one

0.6 x M=0.6Mml of alcohol in solution two

1st equation

0.2L+0.6M=104ml alcohol

times 10 to get whole

2L+6M=1040ml

2nd

same for this equation

10L+10M=2000ml

10L+10M=2000

2L+6M=1040

elimination method

=20L+20M=4000

-

=20L+60M=10400

-40M=-6400

M=160ml

2L+6 (160)=1040

2L=1040-960

2L=80

L=40ml

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.