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The sum of two numbers is 27. One number is 2 times as large as the other. What are the numbers?

Sagot :

Denniswalker510idn

Answer:

9 and 18

Step-by-step explanation:

let the numbers be x and 2x

so that x+2x=27

3x=27

x=9

so the numbers are 9 and 18.

I hope this will help

Answer:

  • 9 and 18

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Step-by-step explanation:

It is given that, the sum of two numbers is 27 and one of the number is 2 times as large as the other.

[tex] \\ [/tex]

Let us assume the one number as x and as state in the question, one of the number is 2 times as large as the other (x) . So, the other number will be 2x .

[tex] \\ [/tex]

Now,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + 2x = 27 \:}}} \\ \\[/tex]

Adding like terms we get :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad 3x = 27 \:}}} \\ \\[/tex]

Dividing both sides by 3 we get :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad \frac{3x}{3} = \frac{27}{3} \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad {x} = {9} \:}}} \\ \\[/tex]

So,

  • One of the number is 9.

[tex] \\ [/tex]

Now,

[tex] \\ {\longrightarrow \pmb{\frak {\qquad Other \: number = 2x \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 2(9) \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 18 \:}}} \\ \\[/tex]

Therefore,

  • The two numbers are 9 and 18.
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