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Find the 12th term of the geometric sequence 1, -4, 16,

Sagot :

Answer:

a₁₂ = - 4194304

Step-by-step explanation:

the nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

here a₁ = 1 and r = [tex]\frac{-4}{1}[/tex] = - 4 , then

a₁₂ = 1 × [tex](-4)^{11}[/tex] = - 4194304

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