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The number of moles of each atom present in 5 moles of Cu₃(PO₄)₂ are:
- 15 moles of Cu
- 10 moles of P
- 40 moles of O
Description of Cu₃(PO₄)₂
- 1 mole of Cu₃(PO₄)₂ contains
- 3 moles of Cu
- 2 moles of P
- (2×4) = 8 moles of O
How to determine the mole of each atom
The moles of atom present in 5 moles of Cu₃(PO₄)₂ can be obtained as follow
For Cu
1 mole of Cu₃(PO₄)₂ contains 3 moles of Cu.
Therefore,
5 moles of Cu₃(PO₄)₂ will contain = 5 × 3 = 15 moles of Cu
For P
1 mole of Cu₃(PO₄)₂ contains 2 moles of P.
Therefore,
5 moles of Cu₃(PO₄)₂ will contain = 5 × 2 = 10 moles of P
For O
1 mole of Cu₃(PO₄)₂ contains 8 moles of O.
Therefore,
5 moles of Cu₃(PO₄)₂ will contain = 5 × 8 = 40 moles of O
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The number of moles of copper, phosphorous and oxygen present in the 5 moles of Cu₃(PO₄)₂ are 15, 20 and 40 respectively.
What is stoichiometry?
Stoichiometry of any chemical equation gives idea about the amount of species present before and after the reaction.
Dissociation reaction of Cu₃(PO₄)₂ is shown as below:
Cu₃(PO₄)₂ → 3Cu²⁺ + 2PO₄³⁻
From the stoichiometry of the equation, it is clear that:
1 mole of Cu₃(PO₄)₂ produces 3 moles of copper atom, 2 moles of phosphorous atoms an 8 moles of oxygen atom.
5 moles of Cu₃(PO₄)₂ = produces 3×5=15 moles of Cu
5 moles of Cu₃(PO₄)₂ = produces 2×5=10 moles of P
5 moles of Cu₃(PO₄)₂ = produces 8×5=40 moles of O
Hence required moles of copper, phosphorous and oxygen are 15, 20 and 40 respectively.
To know more about moles, visit the below link:
https://brainly.com/question/19099163
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